DataMuseum.dk

Presents historical artifacts from the history of:

RegneCentralen RC759 "Piccoline"

This is an automatic "excavation" of a thematic subset of
artifacts from Datamuseum.dk's BitArchive.

See our Wiki for more about RegneCentralen RC759 "Piccoline"

Excavated with: AutoArchaeologist - Free & Open Source Software.


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⟦0265b2b19⟧

    Length: 1536 (0x600)
    Names: »TOLIGN.CSV«

Derivation

└─⟦a1337913c⟧ Bits:30002679 PGM1 - indeholder forskellige undervisningsprogrammer
    └─ ⟦this⟧ »TOLIGN.CSV« 

Hex Dump

0x000…020 02 83 71 bd 23 36 2d 06 e2 05 2f 32 2f 53 41 56 45 2e 24 24 24 20 20 20 20 20 64 00 d3 19 01 01   ┆  q #6-   /2/SAVE.$$$     d     ┆
0x020…040 20 50 52 4f 47 52 41 4d 4d 45 54 20 4c 5c 53 45 52 20 54 4f 20 4c 49 47 4e 49 4e 47 45 52 20 41   ┆ PROGRAMMET LØSER TO LIGNINGER A┆
0x040…060 46 20 46 5c 52 53 54 45 20 2f 2f 00 6e 00 d3 13 01 01 20 47 52 41 44 20 4d 45 44 20 32 20 55 42   ┆F FØRSTE // n      GRAD MED 2 UB┆
0x060…080 45 4b 45 4e 44 54 45 20 41 46 20 46 4f 52 4d 45 4e 00 78 00 d3 0d 01 01 20 20 20 41 31 2a 58 20   ┆EKENDTE AF FORMEN x        A1*X ┆
0x080…0a0 2b 20 42 31 2a 59 20 3d 20 43 31 00 82 00 d3 0d 01 01 20 20 20 41 32 2a 58 20 2b 20 42 32 2a 59   ┆+ B1*Y = C1          A2*X + B2*Y┆
0x0a0…0c0 20 3d 20 43 32 00 8c 00 86 20 36 c0 33 00 41 4e 47 49 56 20 54 41 4c 4c 45 4e 45 20 41 31 2c 42   ┆ = C2     6 3 ANGIV TALLENE A1,B┆
0x0c0…0e0 31 2c 43 31 2c 41 32 2c 42 32 2c 43 32 20 49 20 44 45 4e 4e 45 20 52 5b 4b 4b 45 46 5c 4c 47 45   ┆1,C1,A2,B2,C2 I DENNE RÆKKEFØLGE┆
0x0e0…100 20 00 07 00 01 00 96 00 87 10 13 00 02 80 05 2c 07 80 05 2c 0c 80 05 2c 11 80 05 2c 16 80 05 2c   ┆               ,   ,   ,   ,   ,┆
0x100…120 1b 80 05 00 01 00 a0 00 86 10 16 c0 14 00 4c 49 47 4e 49 4e 47 53 53 59 53 54 45 4d 45 52 20 45   ┆              LIGNINGSSYSTEMER E┆
0x120…140 52 20 07 00 01 00 aa 00 86 07 04 c0 02 00 20 20 07 00 01 00 b4 00 86 1b 04 c0 02 00 20 20 07 3b   ┆R                              ;┆
0x140…160 02 80 07 3b 0a c0 07 00 20 2a 20 58 20 2b 20 00 07 3b 07 80 07 3b 0a c0 07 00 20 2a 20 59 20 3d   ┆   ;     * X +   ;   ;     * Y =┆
0x160…180 20 00 07 3b 0c 80 07 00 01 00 be 00 86 1b 04 c0 02 00 20 20 07 3b 11 80 07 3b 0a c0 07 00 20 2a   ┆   ;                 ;   ;     *┆
0x180…1a0 20 58 20 2b 20 00 07 3b 16 80 07 3b 0a c0 07 00 20 2a 20 59 20 3d 20 00 07 3b 1b 80 07 00 01 00   ┆ X +   ;   ;     * Y =   ;      ┆
0x1a0…1c0 c8 00 86 07 04 c0 02 00 20 20 07 00 01 00 d2 00 3e 12 02 80 00 f0 28 00 07 80 00 f0 28 00 49 00   ┆                >     (     ( I ┆
0x1c0…1e0 0c 80 00 f0 28 00 49 00 2d 71 66 00 00 00 20 80 01 00 dc 00 3e 12 11 80 00 f0 28 00 16 80 00 f0   ┆    ( I -qf         >     (     ┆
0x1e0…200 28 00 49 00 1b 80 00 f0 28 00 49 00 2d 71 66 00 00 00 20 80 01 00 e6 00 d1 0c 26 80 02 80 16 80   ┆( I     ( I -qf           &     ┆
0x200…220 21 00 11 80 07 80 21 00 23 00 1d 00 01 00 f0 00 3e 0a 26 80 00 f0 28 00 2d 71 65 00 2c 80 2d 0d   ┆!     ! #       > &   ( -qe , - ┆
0x220…240 01 00 fa 00 d1 15 35 80 0c 80 16 80 21 00 1b 80 07 80 21 00 23 00 1d 1b 3c 80 02 80 1b 80 21 00   ┆      5     !     ! #   <     ! ┆
0x240…260 11 80 0c 80 21 00 23 00 1d 00 01 00 04 01 86 16 22 c0 20 00 4c 49 47 4e 49 4e 47 53 53 59 53 54   ┆    ! #         "   LIGNINGSSYST┆
0x260…280 45 4d 45 54 20 48 41 52 20 45 4e 20 4c 5c 53 4e 49 4e 47 2c 07 00 01 00 0e 01 86 0e 12 c0 10 00   ┆EMET HAR EN LØSNING,            ┆
0x280…2a0 4e 45 4d 4c 49 47 20 28 58 2c 59 29 20 3d 20 28 07 3b 01 00 18 01 86 0f 0c c0 09 00 23 23 23 2e   ┆NEMLIG (X,Y) = ( ;          ###.┆
0x2a0…2c0 23 23 23 23 23 00 2d 04 35 80 26 80 22 00 09 3b 01 00 22 01 86 07 04 c0 01 00 2c 00 07 3b 01 00   ┆##### - 5 & "  ;  "       ,  ;  ┆
0x2c0…2e0 2c 01 86 0f 0c c0 09 00 23 23 23 2e 23 23 23 23 23 00 2d 04 3c 80 26 80 22 00 09 3b 01 00 36 01   ┆,       ###.##### - < & "  ;  6 ┆
0x2e0…300 86 07 04 c0 01 00 29 00 07 00 01 00 40 01 63 07 00 00 00 00 2c 80 2d 00 01 00 4a 01 d3 1d 01 01   ┆      )     @ c     , -   J     ┆
0x300…320 20 46 5c 52 53 54 20 55 4e 44 45 52 53 5c 47 45 53 2c 20 4f 4d 20 44 45 52 20 45 52 20 4e 55 4c   ┆ FØRST UNDERSØGES, OM DER ER NUL┆
0x320…340 4c 45 52 20 50 5d 20 56 45 4e 53 54 52 45 20 53 49 44 45 00 54 01 3e 18 02 80 00 f0 28 00 07 80   ┆LER PÅ VENSTRE SIDE T >     (   ┆
0x340…360 00 f0 28 00 49 00 14 00 11 80 00 f0 28 00 16 80 00 f0 28 00 49 00 14 00 38 00 2d 71 66 00 00 00   ┆  ( I       (     ( I   8 -qf   ┆
0x360…380 43 80 01 00 5e 01 d3 1b 01 01 20 53 5d 20 55 4e 44 45 52 53 5c 47 45 53 2c 20 4f 4d 20 4c 49 47   ┆C   ^      SÅ UNDERSØGES, OM LIG┆
0x380…3a0 4e 49 4e 47 45 52 4e 45 20 45 52 20 50 52 4f 50 4f 52 54 49 4f 4e 41 4c 45 00 68 01 3f 0f 00 00   ┆NINGERNE ER PROPORTIONALE h ?   ┆
0x3a0…3c0 00 00 07 80 1b 80 21 00 16 80 0c 80 21 00 23 00 00 f0 28 00 2d 72 01 00 72 01 86 1f 34 c0 32 00   ┆      !     ! #   ( -r  r   4 2 ┆
0x3c0…3e0 4c 49 47 4e 49 4e 47 45 52 4e 45 20 45 52 20 52 4f 50 4f 52 54 49 4f 4e 41 4c 45 20 4f 47 20 4c   ┆LIGNINGERNE ER ROPORTIONALE OG L┆
0x3e0…400 5c 53 4e 49 4e 47 53 4d 5b 4e 47 44 45 4e 20 45 52 20 07 00 01 00 7c 01 86 15 02 80 07 3b 08 c0   ┆ØSNINGSMÆNGDEN ER     ø      ;  ┆
0x400…420 05 00 2a 58 20 2b 20 00 07 3b 07 80 07 3b 08 c0 05 00 2a 59 20 3d 20 00 07 3b 0c 80 07 00 01 00   ┆  *X +   ;   ;    *Y =   ;      ┆
0x420…440 86 01 5d 04 00 00 01 00 90 01 86 19 28 c0 25 00 4c 49 47 4e 49 4e 47 53 53 59 53 54 45 4d 45 54   ┆  Å         ( % LIGNINGSSYSTEMET┆
0x440…460 53 20 44 45 54 45 52 4d 49 4e 41 4e 54 20 45 52 20 4e 55 4c 2e 00 07 00 01 00 9a 01 86 11 18 c0   ┆S DETERMINANT ER NUL.           ┆
0x460…480 16 00 44 45 52 20 45 52 20 49 4e 47 45 4e 20 4c 5c 53 4e 49 4e 47 45 52 07 00 01 00 a4 01 80 03   ┆  DER ER INGEN LØSNINGER        ┆
0x480…4a0 01 00 ae 01 6b 03 01 00 b8 01 d2 05 00 00 20 80 01 00 c2 01 86 1e 32 c0 30 00 44 45 4e 20 45 4e   ┆    k                 2 0 DEN EN┆
0x4a0…4c0 45 20 4c 49 47 4e 49 4e 47 20 48 41 52 20 4b 4f 45 46 46 49 43 49 45 4e 54 53 5b 54 54 45 54 20   ┆E LIGNING HAR KOEFFICIENTSÆTTET ┆
0x4c0…4e0 28 30 2c 30 2c 30 29 20 4f 47 07 00 01 00 cc 01 d2 05 00 00 43 80 01 00 d6 01 86 1d 30 c0 2e 00   ┆(0,0,0) OG          C       0 . ┆
0x4e0…500 4c 5c 53 4e 49 4e 47 53 4d 5b 4e 47 44 45 4e 20 42 45 53 54 5d 52 20 41 46 20 44 45 20 54 41 4c   ┆LØSNINGSMÆNGDEN BESTÅR AF DE TAL┆
0x500…520 53 5b 54 20 28 58 2c 59 29 2c 20 44 45 52 07 00 01 00 e0 01 86 13 1c c0 1a 00 50 41 53 53 45 52   ┆SÆT (X,Y), DER            PASSER┆
0x520…540 20 49 20 44 45 4e 20 41 4e 44 45 4e 20 4c 49 47 4e 49 4e 47 07 00 01 00 ea 01 a3 04 2c 80 01 00   ┆ I DEN ANDEN LIGNING        ,   ┆
0x540…560 10 27 d6 00 00 00 03 41 31 00 00 03 42 31 00 00 03 43 31 00 00 03 41 32 00 00 03 42 32 00 00 03   ┆ '     A1   B1   C1   A2   B2   ┆
0x560…580 43 32 00 00 04 4e 55 4c 00 00 04 44 45 54 00 00 07 44 45 54 4e 55 4c 00 00 05 44 45 54 31 00 00   ┆C2   NUL   DET   DETNUL   DET1  ┆
0x580…5a0 05 44 45 54 32 00 00 04 54 41 4c 00 00 00 00 1a 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00   ┆ DET2   TAL                     ┆
0x5a0…5c0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00   ┆                                ┆
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