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⟦11087d12a⟧ Ada Source

    Length: 4096 (0x1000)
    Types: Ada Source
    Notes: 03_class, FILE, R1k_Segment, e3_tag, procedure Test_Tree, seg_045797

Derivation

└─⟦8527c1e9b⟧ Bits:30000544 8mm tape, Rational 1000, Arrival backup of disks in PAM's R1000
    └─ ⟦cfc2e13cd⟧ »Space Info Vol 2« 
        └─⟦this⟧

E3 Source Code



with Abstract_Tree, Lexical, Text_Io;

procedure Test_Tree is
    I : Integer;
    B : Boolean;
    A1, A2, A3, A4, A5 : Abstract_Tree.Object;
begin
    A1 := Abstract_Tree.Make_Node (Lexical.Equ,
                                   Abstract_Tree.Make_Node ("JOUEUR", "ETAT"),
                                   Abstract_Tree.Make_Node ("ALLUME", ""));

    A2 := Abstract_Tree.Make_Node
             (Lexical.Equ, Abstract_Tree.Make_Node
                              (Lexical.Etat_Lien, "SAC", "DAGUE"),
              Abstract_Tree.Make_Node (Lexical.Lie));
    A3 := Abstract_Tree.Make_Node
             (Lexical.Equ, Abstract_Tree.Make_Node ("PIECE_COURANTE", ""),
              Abstract_Tree.Make_Node ("CUISINE", ""));
    A2 := Abstract_Tree.Make_Node (Lexical.Ou, A2, A3);

    A3 := Abstract_Tree.Make_Node ("ALLER", "NORD", "");

    Text_Io.Put_Line ("-----------------------------------------");
    Abstract_Tree.Dump (A1);
    Text_Io.Put_Line (Abstract_Tree.Node_Type'Image
                         (Abstract_Tree.What_Type (A1)));
    B := Abstract_Tree.Evaluate_Node (A1);
    Text_Io.Put_Line ("Result: " & Boolean'Image (B));

    Text_Io.Put_Line ("-----------------------------------------");
    Abstract_Tree.Dump (A2);
    Text_Io.Put_Line (Abstract_Tree.Node_Type'Image
                         (Abstract_Tree.What_Type (A2)));
    B := Abstract_Tree.Evaluate_Node (A2);
    Text_Io.Put_Line ("Result: " & Boolean'Image (B));

    Text_Io.Put_Line ("-----------------------------------------");
    Abstract_Tree.Dump (A3);
    Text_Io.Put_Line (Abstract_Tree.Node_Type'Image
                         (Abstract_Tree.What_Type (A3)));
    B := Abstract_Tree.Evaluate_Node (A3);
    Text_Io.Put_Line ("Result: " & Boolean'Image (B));


    Text_Io.Put_Line ("-----------------------------------------");
end Test_Tree;

E3 Meta Data

    nblk1=3
    nid=3
    hdr6=4
        [0x00] rec0=1a rec1=00 rec2=01 rec3=03c
        [0x01] rec0=17 rec1=00 rec2=02 rec3=000
        [0x02] rec0=05 rec1=00 rec2=02 rec3=000
    tail 0x217474e6c864b5bfb02b6 0x42a00088462060003
Free Block Chain:
  0x3: 0000  00 00 03 fc 80 23 73 74 72 61 63 74 5f 54 72 65  ┆     #stract_Tre┆